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Current draw of a 3511KV 5407L with no load on 2s or 3s lipo? Need some help here.
Current draw of a 3511KV 5407L with no load on 2s or 3s lipo?
I suspect that my feigao has partiallly demagnetised. Right now i am having a current draw of 6A unloaded on 2S lipo. Is this normal? |
That sounds pretty high. I will look later on and I think I have one of those laying around somewhere and a wattmeter. I will try to give a comparison, but usually its only 1 or 2 amps from what I have seen.
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My 7XL will draw 6.5 amps no load on 6s lipo... so it could be right. Maybe check Fiegao website for idle currents?
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No prod bob.
It's probably right... Fiegaos aren't exactly made with high quality control, so everyone's results may vary a bit. |
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Well it all makes sense now. :D All tested are 2 poles motors. |
I don't understand your last post, a stator is the stationary portion of the magnetic field. Basically its the windings in the motor. So as I like to tell people who walk up to me and start speaking spanish: "No Nintendo."
Jeff |
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I was just trying to be funny. How am I not right? The stator is the stationary part of a brushless motor. It's also the stationary coils of an alternator or generator, or any motor type that uses a winding that is stationary position usually on the outside of the rotor or armature as the case may be. In an outrunner it's still the stationary portion of the motor.
I guess if you go by a wikipedia definition or something then I could be wrong. I guess you are referring to slotted vs slotless? (idk I’m asking) Jeff |
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"No entiende" is spanish for "don't understand."
It's no big deal I was just missing what you were saying, I misunderstood what you were saying. It would seem to me that a slotted motor would have a lower idle current than a non slotted motor (air core) due to having more inductance, thus more impedance (and lower Kv) than an aircore motor. Is this correct? And how do you measure idle current? With the motor at a very low RPM without a load? What's the test procedure? Jeff |
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All things being equal, having an iron core would do exactly as you say, but because of the iron core there would be a larger resistance to changes in current flow ie: inductance so that would lower the Kv and increase the impedance which changes with frequency (RPM).
"But the savings in copper is offset by having a stator coil." And you meant to say core right? I am not trying to nit pick , just understand. Jeff |
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Sorry it took me so long. 3.4A on 2S, 5A on 3S.
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