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MetalMan
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12.14.2005, 09:17 PM

Lipos are much more simple than it seems you are thinking. Take two Lipo cells (at a similar voltage, + or - 0.05v), and stick them in parallel, and their voltage will equalize. In effect, one cell will be charged, and the other discharged. The reason for having such a small difference in voltage between the two cells is so that the lower cell will not be charged by the higher one at such a high rate.
Notice that I did not mention anything about the capacities of the cells. One could connect two cells of completely different capacities (like 1000mah and 4000mah) in parallel to give 5000mah and the sum of the amp rates. During a discharge, both cells will remain at the same voltage (theoretically, but the resistance of wire could affect it). The draw from each cell is a function of the resistance of each cell. For example, a 1000mah 10C cell(10amps) will have a resistance roughly 4 times greater than a 4000mah 10C cell (40amps). If both cells were to contain an identical composition (excluding size), then at a 50amp discharge the 1000mah will take 10amps of the load and the 4000mah will take 40amps. Obviously, no two cells will be some much alike as to allow such theoretical-ness, but I am just throwing the idea out there.
This same process goes for charging. Take both of the previous cells as examples. At a 5amp charge (1C for the combined pack), the 1000mah will take in 1amp and the 4000mah 4 amps.

The important thing to remember is that the cells will always be at the same voltage (neglecting wire resistance), and the internal resistance of the cells will determine the actual number of amps being pulled from (or put in to) each cell.

P.S., if you haven't seen a real-world application for parallel batteries, you need to get out more, my friend :).


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