Quote:
Originally Posted by BrianG
Not if the gearing and the motor is the same. A=V/R. If voltage goes up, and resistance stays the same, current will go up. I'd have to drop gearing and/or use a lower kv motor (increasing R) to reduce current.
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But Power = current X voltage ---- P=IV
So to produce the same power with higher voltage, current drops. In effect this equation is more direct to the VI relationship than I = V/R isnt it?