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Marvin
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Quick Question - 11.03.2009, 05:49 PM

Now, it is generally accepted that same power, higher voltage (lower current) is more efficient than same power, lower voltage, (more current).

To have higher efficiency, you surely must have less resistance. R=V/I. If current increases (and as resistance and current are inversely proportional), resistance must decrease?

I understand that more current = more heat, which increases resistance, but surely, the above equation shows that resistance does not increase with current.

What have I missed?


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