Quote:
Originally Posted by squeeforever
...Ok, so the + of the load goes to the common, and the - goes to the normally open, then the anode with a resistor goes to the common as well, and the cathode goes to?
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If I follow what you're saying: No. You're probably overthinking it.
First, put the LED in series with the resistor.
Then, you are effectively placing that LED/resistor "circuit" in parallel with the rest of your load/circuit.