[BrianG]

You have to remember the resistive losses come from I^2*R. True, resistance is higher in a higher turn motor because of the added turns and thinner wire, but less current makes a bigger difference because that is the squared part of the equation. So, as long as the top speed is the same (load), a higher voltage on a lower kv will result in the same amount of work and same overall power as a lower kv/voltage setup.