Quote:
Originally Posted by BrianG
Again, it's not a certain fixed value. The higher the current flow, the higher the voltage drop. The 1n4001 will drop 0.8v @ ~.2A. Other resistors, such as 3A diodes (which are larger to handle V*I power losses) will drop less voltage at that same current.
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Okay, so I should just be using 7 diodes if I'm dropping 12V to 7V?