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Originally Posted by crazyjr
Thanks wasn't sure how it worked
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Jusdging by the fact it has an input and output connector, the eagletree most likely measures current by placing a very small precision resistance in series with the load, something like 0.001 ohms. Then it measures the voltage drop across this tiny resistance and calculates the current. So, let's say it is a 0.001 ohm shunt, and you are drawing 100A, it would have 0.1v dropped across it. They keep it small so it has little effect on the overall voltage. Then, it measures the voltage like any normal voltmeter would.
So, if you put it inline with only one pack, it will measure half the full system voltage, but the current will be right (current is the same in a series circuit). Obviously, this will also affect your power readings. Just multiply the power by two as well...