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BrianG
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01.14.2011, 03:21 PM

You have to remember the resistive losses come from I^2*R. True, resistance is higher in a higher turn motor because of the added turns and thinner wire, but less current makes a bigger difference because that is the squared part of the equation. So, as long as the top speed is the same (load), a higher voltage on a lower kv will result in the same amount of work and same overall power as a lower kv/voltage setup.
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