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Originally Posted by glassdoctor
As long as you realise there is no free lunch. The price for the voltage boost is less runtime (2x the voltage means 1/2 the runtime) PLUS the 10% loss in efficiency from the device. And the battery will see more current drain... maybe it can handle it ok. THey are pretty good batteries.
A much better solution IMO is to use more cells to get the voltage you want... you get full runtime and no losses.
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I don't think that 2x the voltage means 1/2 the runtime. The runtime would be halved only if the current doubled. As long as the current draw remains the same, then a voltage increase will not decrease the runtime.
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