Amperage and MAH how is it doubled ?

[SpeedAssault]

Originally Posted by squeeforever

Yea, he was definately wrong.

The only somewhat confusing part of all of it is parallel. 2 3S 3000mah packs in parallel will be 3S 6000mah, like pimp said, but it would still be 30C. Differance is, the amps double as well, just not the C. Its pretty simple one you think about it. A 3S 3000mah 30C pack is 90 amps, but a 3S 6000mah 30C pack is 180. Still 30C, but when the MAH is doubled, so is the amperage since C x Ah = amps. Got it?

Thank u squee,
Wow , thank you for putting it into that example, it makes more sense and easy to folow.
But that is weird to figure, that MAH double and amps double but not the C rating. I thought the C rating had to do with the amp output..?
So what importance is C rating, how is it used ?

How about in series, whats that equation ?
I may want to use two 3s in series

thank you for your help, it really

[JThiessen]

In laymans terms...C rating is basically like the valve size on your garden hose. You can change how fast the fluid goes through it (Amps), and you can change the pressure behind it (Volts), but that valve is always only going to open up so far, thus only allowing so much water through....

[hootie7159]

Originally Posted by JThiessen

In laymans terms...C rating is basically like the valve size on your garden hose. You can change how fast the fluid goes through it (Amps), and you can change the pressure behind it (Volts), but that valve is always only going to open up so far, thus only allowing so much water through....

Wow!!! cliffnotes version i like it!!!!

[SpeedAssault]

I think I got it, except for, if I do in series do I need a lower C than if I do in parallel to equal the same amperage ? or I guess that always stays the same ?

Are these equal ?
Two 5000 3s 30c in series = 5000 6s 30c 150amps

Two 2500 3s 30c in parallel = 5000 3s 30c 150amps

I have it all figure out except for above AND how to figure what a 2200kv motor needs in watts ?

[Finnster]

Originally Posted by SpeedAssault

I think I got it, except for, if I do in series do I need a lower C than if I do in parallel to equal the same amperage ? or I guess that always stays the same ?

Are these equal ?
Two 5000 3s 30c in series = 5000 6s 30c 150amps

Two 2500 3s 30c in parallel = 5000 3s 30c 150amps

I have it all figure out except for above AND how to figure what a 2200kv motor needs in watts ?

its equal amp wise, but obviously the 6s is double the power as voltage is 2X.

Another way to keep is straight in your head is just noting that a given battery equals a discrete amount of energy (& power.) Hooking two batts in series or par does not change the total amount of energy, ie it is two units.

EG. Energy equals power*time or (voltage*amps) * time.
A 3S 5Ah cell equals--> 3*(3.7V) *5Ah= 55.5Wh (watt hours)

So if you take two packs, the total Energy is 111Wh no matter what.

Series: ie 6S 5Ah--> 6*3.7V*5Ah=111Wh
Par: ie 3S 10Ah --->3*3.7V*10Ah=111Wh

You know the guy at the hobby store was FOS, bc according to him:
2x 3S 3Ah packs in series = 6S 6Ah... try the math
3S 3Ah= 33Wh => two packs =66Wh
LHS "magic packs": 6S 6Ah= 133 Wh... nope, fail. You didn't somehow create energy just by changing wires. If you could you'd solve the world's energy problems and win several Nobels for overturning fundamental laws of physics. lol

[SpeedAssault]

Originally Posted by Finnster

its equal amp wise, but obviously the 6s is double the power as voltage is 2X.

Another way to keep is straight in your head is just noting that a given battery equals a discrete amount of energy (& power.) Hooking two batts in series or par does not change the total amount of energy, ie it is two units.

EG. Energy equals power*time or (voltage*amps) * time.
A 3S 5Ah cell equals--> 3*(3.7V) *5Ah= 55.5Wh (watt hours)

So if you take two packs, the total Energy is 111Wh no matter what.

Series: ie 6S 5Ah--> 6*3.7V*5Ah=111Wh
Par: ie 3S 10Ah --->3*3.7V*10Ah=111Wh

You know the guy at the hobby store was FOS, bc according to him:
2x 3S 3Ah packs in series = 6S 6Ah... try the math
3S 3Ah= 33Wh => two packs =66Wh
LHS "magic packs": 6S 6Ah= 133 Wh... nope, fail. You didn't somehow create energy just by changing wires. If you could you'd solve the world's energy problems and win several Nobels for overturning fundamental laws of physics. lol

woosh over my head. I'm not at that level yet.

So regardless of Series or Par I still need a 30c which ever way I go ..?

If the 2200kv is 1250 watts DO I just need 1300 watts of battery power ?

[lincpimp]

Originally Posted by SpeedAssault

woosh over my head. I'm not at that level yet.

So regardless of Series or Par I still need a 30c which ever way I go ..?

If the 2200kv is 1250 watts DO I just need 1300 watts of battery power ?

If you think you need 1250 watts of power to the wheels and you plan to use a motor that is 85% efficient then you will need some thing like 1500 watts of battery power

1250/.85 = 1470

Now the problem iswhere did you get the 1250 from? Someone told you that? Doing the math will get you the numbers, but there are no hard and fast rules on what numbers apply to what vehicle due to the giant amount of variables.

Best to list your setup and intended use and we will do our best to suggest alternatives for lipo power.