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BrianG
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08.17.2009, 10:45 AM

You could conceivably get 7v, 8.3v, 24v, 17v, 15.3v, and 1.7v (may have missed a couple there) from that supply. However, DO NOT simply tie the leads together. In any of those combinations, you would not use the ground lead at all. For example:

- If you want 7v: the + lead would be 12v, and the - lead would go to 5v.
- If you want 8.3v: the + lead would be 12v, and the - lead would go to 3.3v.
- If you want 24v: the + lead would be 12v, and the - lead would go to -12v.
- If you want 17v: the + lead would be 12v, and the - lead would go to -5v.
- If you want 15.3v: the + lead would be 3.3v, and the - lead would go to -12v.
- If you want 1.7v: the + lead would be 5v, and the - lead would go to 3.3v.
and so on...

Also, the output current would be limited by the current capability of the lowest rail. So, if you used the 12v (34A) rail along with the -5v (2A) rail to get 17v, your total current would be limited by the -5v line, which is 2A.

Last edited by BrianG; 08.17.2009 at 11:01 AM.
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KaztheMinotaur
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08.17.2009, 12:00 PM

Bah... Well that doesn't get me anywhwere then...

17V @ 2A doesn't do much good.
   
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zeropointbug
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08.17.2009, 12:27 PM

Why don't you just use the 12v rail, you don't need any higher voltage than that. What charger were planning on using it with?


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KaztheMinotaur
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08.17.2009, 12:30 PM

I can, I was just trying to see if I can get the voltage up. I'm going to get 2chargers so I can charge 2 5S 5000 mah batteries at 5A at the same time.
   
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whitrzac
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08.17.2009, 12:33 PM

Quote:
Originally Posted by KaztheMinotaur View Post
I can, I was just trying to see if I can get the voltage up. I'm going to get 2chargers so I can charge 2 5S 5000 mah batteries at 5A at the same time.
put a 10ish ohm power resistor on between 5v and a ground

http://www.radioshack.com/product/in...ductId=2062288
   
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KaztheMinotaur
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08.17.2009, 12:45 PM

Yeah, I have one. Thats on my to do list tonight. I'm going to practice on my old power supply first.
   
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