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03.15.2010, 10:42 AM
Well, the numbers do add up, but that 2" of ballooning is really artificially increasing your speed. If you use the base value of 5.65" for tire size and not enter any ballooning, the speed is ~40mph. Don't forget, the ballooning value is that added radius you get. So, if your tires are 6" in diameter normally, and they become 8" in diameter when ballooning, that is a 1" change in radius. A 2" ballooning value on a 5.65" tire means that the tire is 9.65" in diameter, which is very doubtful. The whole ballooning thing is described in the little help questionmark.
Also, to make it easier to post that information here, there is an "Export Values" button. You can then copy/paste from that. Also, if you save this info somewhere on your computer, you can later repaste that info back in using the "Import Values" button. Anyway, here is a more reasonable output with more normal values:
Differential Ratio: 3.3076923076923075
Transmission Ratio: 1
Other Ratio: 1
Spur Tooth Count: 62
Pinion Tooth Count: 16
Total Voltage: 18.5
Motor KV: 1650
Tire Diameter (inches): 5.65
Tire Ballooning (inches): .5
Motor Current Draw: 0
Motor Coil Resistance: 0.01
Spur/Pinion Ratio: 3.88 : 1
Total Ratio: 12.81731 : 1
Tire Circumference (inches): 20.89 inches (530.65 mm)
Rollout: 1.63:1
Total Motor Speed: 30525 RPM
Vehicle Speed: 47.12 mph (75.68 km/h)
Effective KV Value: 1650
KT constant: 0.82 oz-in/A
Motor Torque: Amperage not specified...
Final Torque: Amperage not specified...
Final Power: Amperage not specified...
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