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BrianG
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05.19.2007, 08:16 PM

OK, thanks! That makes sense. I guess I just didn't understand the statement:

Quote:
Originally Posted by GriffinRU
If controller doesn't open FET's then BackEMF from motor will be rectified by built-in diodes and will be charging battery, if battery voltage will be less then backEMF+voltage drop. You can optimize this process if you open FETs in sync with diodes, then you will cut off diodes voltage drop and losses.
If you noticed braking can be done with only one side, while recuperating involved both.
My confusion stems from the diode aspect. I know the diode is built into the FETs. So, if the FET simply shorts the phases, how can you eliminate the v drop of the diodes?
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