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  (#151)
mjderstine
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03.23.2009, 02:29 PM

awesome, now i can get the card, and the esc at one awesome store. good stuff.
   
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  (#152)
Joey
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04.13.2009, 03:26 PM

Any news on if it handles 5s????????????
   
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  (#153)
BrianG
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04.13.2009, 03:30 PM

I did run it a little bit on 5s. It arms and runs. Just don't know for how long. I didn't want to run it for too long as it was on a 1512/2d and the current would be rather high.
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Old
  (#154)
lincpimp
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04.13.2009, 05:18 PM

Has anyone tried this with a sensored motor yet?
   
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  (#155)
BrianG
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04.13.2009, 05:22 PM

Sensored? What's that?
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  (#156)
Joey
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04.14.2009, 12:19 AM

Quote:
Originally Posted by BrianG View Post
I did run it a little bit on 5s. It arms and runs. Just don't know for how long. I didn't want to run it for too long as it was on a 1512/2d and the current would be rather high.
Wouldnt the current be lower on 5S than 4S?
   
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  (#157)
BrianG
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04.14.2009, 12:24 AM

Not if the gearing and the motor is the same. A=V/R. If voltage goes up, and resistance stays the same, current will go up. I'd have to drop gearing and/or use a lower kv motor (increasing R) to reduce current.

Last edited by BrianG; 04.14.2009 at 09:46 AM.
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  (#158)
himalaya
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04.14.2009, 01:47 AM

Quote:
Originally Posted by BrianG View Post
Not if the gearing and the motor is the same. A=V/R. If voltage goes up, and resistance stays the same, current will go up. I'd have to drop gearing and/or use a lower kv motor (reducing R) to reduce current.
Guess you were trying to say (increasing R & inductance) to reduce current.


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  (#159)
BrianG
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04.14.2009, 09:46 AM

lol, yeah, I meant increasing R...original post edited.

I have an excuse: it was late and I was tired.
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  (#160)
Joey
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04.14.2009, 06:59 PM

Quote:
Originally Posted by BrianG View Post
Not if the gearing and the motor is the same. A=V/R. If voltage goes up, and resistance stays the same, current will go up. I'd have to drop gearing and/or use a lower kv motor (increasing R) to reduce current.
But Power = current X voltage ---- P=IV

So to produce the same power with higher voltage, current drops. In effect this equation is more direct to the VI relationship than I = V/R isnt it?
   
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  (#161)
littlegiant
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04.14.2009, 07:55 PM

Quote:
Originally Posted by Joey View Post
But Power = current X voltage ---- P=IV

So to produce the same power with higher voltage, current drops. In effect this equation is more direct to the VI relationship than I = V/R isnt it?
If u are running on 5S without changing your gearing, your truck will be running faster. Which means that the power is higher. P=IV and so your current will definitely be higher.

In order for your 5S to have a lower current than a 4S, it should be geared to your current 4S speeds. If your 5S is running at a higher speed, you are just running your motor at a higher wattage.
   
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  (#162)
Cain
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05.08.2009, 09:40 PM

Has anyone taken a look at the speedpassion ESC internals and compared it to this one? Have heard that they are basically the same.
   
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  (#163)
lutach
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05.09.2009, 07:59 AM

Quote:
Originally Posted by Cain View Post
Has anyone taken a look at the speedpassion ESC internals and compared it to this one? Have heard that they are basically the same.
They are the same.
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  (#164)
Cain
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05.09.2009, 09:46 AM

got a link to this discussion?
   
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  (#165)
lutach
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05.09.2009, 10:16 AM

Quote:
Originally Posted by Cain View Post
got a link to this discussion?
There's no link, it's just the facts. You can also ask Hobbywing who's a member of RCM.
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