6s on M Monster

[Pdelcast]

Originally Posted by BrianG

Can you define "working harder" because from my testing, it appears that for a given load, higher input voltages (to a degree) yields highest efficiency.

Yes, it yields higher efficiency, but it's harder on the parts due to higher partial currents -- even though the average current is lower, the I^2R losses are higher in the FETs.

[BrianG]

Originally Posted by Pdelcast

Yes, it yields higher efficiency, but it's harder on the parts due to higher partial currents -- even though the average current is lower, the I^2R losses are higher in the FETs.

lol, straight from the horse's mouth!

Thanks for that info. Makes sense. So, the FETs work harder because of the higher partial currents, but does the coil or diode (assuming it's not running into saturation) work any harder?

[Pdelcast]

Originally Posted by BrianG

lol, straight from the horse's mouth!

Thanks for that info. Makes sense. So, the FETs work harder because of the higher partial currents, but does the coil or diode (assuming it's not running into saturation) work any harder?

Yes, both do -- the diode recirculates longer, and the peak currents are higher in the coil. Capacitor currents are higher too, but they don't even get slightly warm...